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Area Problems Solved Questions For IBPS, SBI and Other Bank Exams - Page 1

You will find 28 problems in 7 pages..

Area Problems Solved Questions (Page 1 of 7)

Dear Reader,
Below you will find important solved questions of age problems. These questions will help you in preparation for all bank exams including IBPS, SBI, RRB and other banks.

Question 1

If the sides of a square are 'a' units long is increased by 40% then the extra area (in unit2) covered by the square is :
a) (24/25)a2 b) a2 /25 c) (7/5)a2 d) none of these

Answer: a) (24/25)a2

Solution:

Let the side of a square = a units
Then the original area = a2 unit2
Length of the new square = 140/100 x a = 7a/5 unit2
Then the area of new square = 49a2 / 25 unit2.
Now, the extra area covered by the square = area of new square - the original area
49a2 / 25 unit2 - a2 unit2 =24a2 / 25 unit2.

Hence the answer is (24/25)a2


Question 2

If the breadth of a rectangle with area A is increased by 20% and B is the difference between the area of the two rectangles then which of the following is true?
a) A = 5B b) 5B = A c) A=B d) A=2B

Answer: b) 5B = A

Solution:
Let the length of the rectangle be l and breadth be b.
then the original area of the rectangle = A = lb....(1)

Now, the length of the new rectangle is l
And, the breadth of the new rectangle = 120/100 x b = 6b/5
Then, the area of the new one = (6/5)lb
Therefore, the difference between two rectangles = B = (6/5)lb - lb = (1/5)lb...(2)
From (1) and (2),
B = (1/5)A
5B = A

Hence the answer is option b.


Question 3

A rectangle is made from a square of 1 unit long by increasing one pair of opposite sides by 20% then the area of the rectangle is :
a) 6/5 unit2 b)1/5 unit2 c)6 unit2 d)5 unit2

Answer: a) 6/5 unit2

Solution:
Let the side of the square = a = 1 unit
Then the length of the rectangle = side of the square after increasing = l
l = 120a/100 = 6a/5 = 6/5 (since a = 1)
l = 6/5 and breadth b = a = 1
Then the area of the rectangle = lb = 6/5 x 1 unit2
Hence the answer is 6/5 unit2.


Question 4

The pair of opposite side of a rectangle is increased and decreased by 20% and 10% respectively then the area of the rectangle is increased or decreased by;
a)10% b)20% c)28% d)8%

Answer: d) 8%

Solution:

Let the original length = L
and the original breadth = B
Then the area = LB

New length = 120/100 x L = 12L/10
New breadth = 90/100 x B = 9B/10
New area = 12L/10 x 9B/10 = 108LB/100
increase in area = 108LB/100 - LB = 8LB/100
Then increase percentage = 8LB/100 / LB x 100 = 8%
Hence the answer is 8%


Area Problems Solved Questions (Page 1 of 7)

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