## Area Problems Solved Questions For IBPS, SBI and Other Bank Exams - Page 4

You will find 28 problems in 7 pages..

Area Problems Solved Questions (Page 4 of 7)

Question 1

The dimension of a rectangular plot is 36m x 20m. When the breadth is decreased to 14.4 m, what will be the length of the plot if the area remains same?

a) 28.4m b) 50m c) 52.2m d) 34m

Solution :

Dimension of the rectangle plot = 36m x 20m.
Length of the plot l = 36m
Breadth of the plot b = 20m.
Area of the plot = lb = 36 x 20 = 720 m2 .
Since breadth is decreased to 14.4 m, the new breadth = 14.4 m
Note that, the area is unchanged.
new length x new breadth = 720 m2 .
New length = 720 m2 / 14.4 m = 50m.
Hence, the required answer is 50m.

Question 2

The perimeter of a rectangle is 208 cm and breadth is 40% less than the length. Find the area of the rectangle.

a) 1585 cm2 b) 3505 cm2 c) 1595 cm2 d) 2535 cm2

Solution :

Let L and B be the length and breadth of a rectangle.
Then, perimeter = 2(L + B) units.
Given that, perimeter = 2(L + B) = 208 cm
Therefore, L + B = 104 cm ………(1)
Breadth of the rectangle is 40% less than the length.
i.e., Breadth = L – 40% of L
b = L – 40 L / 100 = 60 L / 100 cm
Sub. B value in (1), we get
L + 60L / 100 = 104 cm
160L / 100 = 104 cm
L = 65 cm
Then, L + B = 65 + B = 104 => B = 39 cm
Now, L = 65 cm and B = 39cm
Area = LB = 65 x 39 cm2 .
= 2535 cm2
Hence the answer is option d.

Question 3

Find the area of the rectangle whose perimeter is 412 cm and difference between the length and breadth is 46m.

a) 10080 cm2 b) 10200 cm2 c) 11080 cm2 d) 9080 cm2

Solution :

Let L and B be the length and breadth of the rectangle.
Perimeter of the rectangle = 2(L + B) units.
Given that, perimeter = 412 cm
L + B = 206 cm ………(1)
Difference between the length and breadth = L - B = 46 m …….(2)
Adding (1) and (2), we get = 2L = 252 cm
L = 126 cm.
B = 80 cm.
Area = LB = 126 x 80 = 10080 cm2.

Question 4

The length of a rectangular plot is 40% more than its breadth. It cost Rs.12288 to build a wall around the plot at Rs.128 per meter. Find the area of the plot.

a) 560 m2 b) 840 m2 c) 390 m2 d) 440 m2

Solution :

Let L and B be the length and breadth of the rectangle.
Length is 40% more than the breadth. i.e., L = B + 40% of B
L = B + 40L / 100 = 140B / 100 cm.
Total cost to build a wall around the plot is Rs. 12288 at Rs.128 per meter.
Circumference of the plot = Rs. 12288 / Rs.128 = 96 meters.
i.e., Perimeter = 2(L + B) = 96 m.
Therefore, L + B = 48 m ……1)
Substituting the values of L and B in above eqn, we get,
L + B = 140B / 100 + b = 240B / 100 = 48
B = 4800 / 240 = 20 m
L = 48 – 20 = 28 m.
Area = LB = 20 x 28 = 560 m2.

Area Problems Solved Questions (Page 4 of 7)

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