## Percentage Solved Questions For IBPS, SBI and Other Bank Exams - Page 3

You will find 31 problems in 8 pages..

Percentage Problems Solved Questions (Page 3 of 8)

Question 1

Mr.Madhan purchases some articles with market price of Rs.2400. If the tax of the article increased from 10/3 % to 7/2 % then what will be the difference in his purchases.
a)Rs 5 b)Rs 3 c)Rs 1 d)Rs 2

Solution:

Given that the market price of the articles is Rs.2400.

7/2 % of Rs.2400 = 7/2 x 1/100 x 2400
10/3 % of Rs.2400 = 10/3 x 1/100 x 2400

Then, the required difference = [7/2 x 1/100 x 2400] - [10/3 x 1/100 x 2400]

==> [7/2 - 10/3] x 1/100 x 2400 = 1/6 x 24 = Rs.3

Question 2

A seller takes 5% on all his sales upto Rs. 5000 and 4% on all his sales exceeding Rs.5000. He returns RS.67150 to his owner after deducting his commission. Then the amount of his total sales is :
a)Rs 90000 b)Rs 70000 c)Rs 75000 d)Rs 95000

Solution:

Let his total sales be Rs.X
Now, Total sales - commission = Rs.67150
X - [ 5% of 5000 + 4% of (X-5000)] = 67150
X - [5/100 x 5000 + 4/100 x 5000] = 67150
X - [250 - 200 +4X/100 ] = 67150
X - 50 - 4X/100 = 67150
96X = [50 + 67150]100
X = 6720000/96 = 70,000
Hence he made total sales of Rs.70,000

Question 3

A machine worth Rs.1,50,000 is insured to 80% of its cost. The machine becomes useless by an accident and the insurance company paid 90% of the insurance. Then the difference between the cost of the machine and the amount received is:
a)Rs 42000 b)Rs 50000 c)Rs 63000 d)Rs 28000

Solution :

Amount paid to machine by insurance company:
90% of 80% of the original cost of the machine
90/100 x 80/100 x 1,50,000
7200 x 15
Rs.108000

Then, the required difference is Rs[150000 - 108000] = Rs. 42,000