## SBI Sample Problems Based On Ratio

Dear Reader,

Below are four problems dealing with ratio of numbers.

**Question 1**

The ratio of four numbers is 1:3:5:7 and the sum of the numbers is 32. Then the largest of these numbers is:

a)14 b)17 c)19 d)15

**Answer:** a)14

Solution:

Given ratio of the numbers is 1:3:5:7

then the numbers are x , 3x, 5x and 7x

Given that, x + 3x + 5x + 7x = 32

16x = 32

x = 2

Now, the largest of these numbers is 7x = 7(2) = 14.

Hence the answer is 14.

**Question 2**

The ratio of two numbers is 11:5 and the product of these numbers is 220. Then the smallest one is:

a)15 b)10 c)13 d)12

**Answer :** b)10

Solution :

Given ratio is 11:5

Then the numbers are 11X and 5X

Given that, 11X x 5X = 220

55X^{2} = 220

55X^{2} = 5 x 4 x 11

55X^{2} = 55 x 2^{2}

X = 2

Then, the smallest number is 5X = 10

**Question 3**

Three numbers are in the ratio 2:3:4 and their sum is 450. Then the sum of their square is :

a) 22500 b) 45000 c) 15000 d) 72500

**Answer:** d) 72500

Solution:

Given ratio 2:3:4

Then, the numbers are 2X, 3X and 4X

2X + 3X + 4X = 450

9X = 450

X = 50

Therefore, the numbers are 100, 150 and 200.

And their squares are 10000, 22500 and 40000.

Then, the required sum is 10000 + 22500 + 40000 = 72500

Hence, the answer is 72500

**Question 4**

Two numbers are in the ratio 7:3 and the sum of the numbers is 240 then their difference is:

a) 98 b) 88 c) 96 d) 78

**Answer:** c) 96

Solution:

Given ratio 7:3

Then, the numbers are 7X, 3X

7X + 3X = 240

10X = 240

X = 24.

Therefore the numbers are 168 and 72.

Hence the required difference = 168 - 72 = 96.